EATING OUT AND YOUR AGE

[magpie in the 80's]

It takes less than a minute.
This is not one of those waste of time things, it's fun.

1. First of all, pick the number of times a week that you would like to go out to eat.
(more than once but less than 10)
2. Multiply this number by 2 (just to be bold)
3. Add 5
4. Multiply it by 50
5. If you have already had your birthday this year add 1757..............If you haven't, add 1756.
6. Now subtract the four digit year that you were born.
7.You should have a three digit number.
The first digit of this was your original number. ( I.e., How many times you want to go out to restaurants in a week.)
The next two numbers are YOUR AGE !
(Oh YES, it is!)

[Psyber]

Yup, it works!

[Coorong]

Bugger, 2 times a week and 57....spot on

[JAS]

Very clever...I get 2 times a week and 46...sad but true

Regards
JAS

[magpie in the 80's]

:lol: Very clever...I get 2 times a week and 46...sad but true

Regards
JAS

what's sad about eating out twice a week

[Pseudo]

It takes less than a minute.
This is not one of those waste of time things, it's fun.

1. First of all, pick the number of times a week that you would like to go out to eat.
(more than once but less than 10)
2. Multiply this number by 2 (just to be bold)
3. Add 5
4. Multiply it by 50
5. If you have already had your birthday this year add 1757..............If you haven't, add 1756.
6. Now subtract the four digit year that you were born.
7.You should have a three digit number.
The first digit of this was your original number. ( I.e., How many times you want to go out to restaurants in a week.)
The next two numbers are YOUR AGE !
(Oh YES, it is!)

1. x any integer in in (2,9)
2. 2x
3. 2x+5
4. 100x+250
5. 100x+2006+y where y=1 for birthday passed, y=0 otherwise
6. 100x+(2006-birthyear+y)
= 100x + age.

first digit = floor((100x+age)/100)
= floor(x + age/100)
= x

next two digits = (100x+age) mod 100
= age

It won't work if your age is greater than 100.

There's nothing like simple mathematics for taking the magic out of these things

[Thiele]

Correct i do eat out 2 times a week and i'am 28

[Strawb]

its true i am lucky to eat out once a week and i am 25

[RustyCage]

It takes less than a minute.
This is not one of those waste of time things, it's fun.

1. First of all, pick the number of times a week that you would like to go out to eat.
(more than once but less than 10)
2. Multiply this number by 2 (just to be bold)
3. Add 5
4. Multiply it by 50
5. If you have already had your birthday this year add 1757..............If you haven't, add 1756.
6. Now subtract the four digit year that you were born.
7.You should have a three digit number.
The first digit of this was your original number. ( I.e., How many times you want to go out to restaurants in a week.)
The next two numbers are YOUR AGE !
(Oh YES, it is!)

1. x any integer in in (2,9)
2. 2x
3. 2x+5
4. 100x+250
5. 100x+2006+y where y=1 for birthday passed, y=0 otherwise
6. 100x+(2006-birthyear+y)
= 100x + age.

first digit = floor((100x+age)/100)
= floor(x + age/100)
= x

next two digits = (100x+age) mod 100
= age

It won't work if your age is greater than 100.

There's nothing like simple mathematics for taking the magic out of these things

That's SIMPLE mathematics? Damn!!!

[johntheclaret]

It takes less than a minute.
This is not one of those waste of time things, it's fun.

1. First of all, pick the number of times a week that you would like to go out to eat.
(more than once but less than 10)
2. Multiply this number by 2 (just to be bold)
3. Add 5
4. Multiply it by 50
5. If you have already had your birthday this year add 1757..............If you haven't, add 1756.
6. Now subtract the four digit year that you were born.
7.You should have a three digit number.
The first digit of this was your original number. ( I.e., How many times you want to go out to restaurants in a week.)
The next two numbers are YOUR AGE !
(Oh YES, it is!)

1. x any integer in in (2,9)
2. 2x
3. 2x+5
4. 100x+250
5. 100x+2006+y where y=1 for birthday passed, y=0 otherwise
6. 100x+(2006-birthyear+y)
= 100x + age.

first digit = floor((100x+age)/100)
= floor(x + age/100)
= x

next two digits = (100x+age) mod 100
= age

It won't work if your age is greater than 100.

There's nothing like simple mathematics for taking the magic out of these things

Spoil sport you

[Dogwatcher]

Hmmm I read this thread and thought it was about an entirely different subject!

[Punk Rooster]

Hmmm I read this thread and thought it was about an entirely different subject!

I too...

[Dog_ger]

Bloody hell...... 2x and I am 50...!!!

[Rik E Boy]

The older you get, the more often you have to eat out ha ha.

regards,

REB