by Punk Rooster » Sat Dec 09, 2006 10:16 am
Ralph Wiggum wrote:That's where I saw the leprechaun. He told me to burn things
by Dutchy » Sat Dec 09, 2006 10:29 am
by SCD » Sat Dec 09, 2006 10:31 am
by Punk Rooster » Sat Dec 09, 2006 10:37 am
Ralph Wiggum wrote:That's where I saw the leprechaun. He told me to burn things
by mighty_tiger_79 » Sat Dec 09, 2006 10:54 am
by mighty_tiger_79 » Sat Dec 09, 2006 11:01 am
by mal » Sat Dec 09, 2006 11:52 am
by rooburger » Sat Dec 09, 2006 1:59 pm
by Frosty » Sun Dec 10, 2006 10:44 pm
by mighty_tiger_79 » Mon Dec 11, 2006 10:03 am
by RustyCage » Mon Dec 11, 2006 10:11 am
mighty_tiger_79 wrote:FROSTY
i havent played roulette on the computer touch screens that they have but I would think like you mentioned that it would be a good way to play it as you dont have to push and shove to get bets on and people dont know what you are betting on and cant copy you
by Dutchy » Mon Dec 11, 2006 11:21 am
by mighty_tiger_79 » Mon Dec 11, 2006 11:30 am
by Ecky » Mon Dec 11, 2006 1:03 pm
Punk Rooster wrote:I loathe idiots who reply (when I tell them of my Roulette system)- "You can't beat the casino blah blah blah"
mighty_tiger_79 wrote:you assess the board for the last 15 spins and see where the numbers are coming from, if you have just arrived on the table beware of numbers that have repeated, as sometimes when the dealer takes too long too pay out the number will automatically come up again for some reason.
mighty_tiger_79 wrote:thats not a bad strategy because you quite often see numbers from the same third repeating a few times.
by Punk Rooster » Mon Dec 11, 2006 1:11 pm
Ecky wrote:Punk Rooster wrote:I loathe idiots who reply (when I tell them of my Roulette system)- "You can't beat the casino blah blah blah"
I must be one of those "idiots", Punky.![]()
How can your system give any different distribution of payouts than choosing two numbers at random after every spin![]()
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Ralph Wiggum wrote:That's where I saw the leprechaun. He told me to burn things
by Ecky » Mon Dec 11, 2006 1:22 pm
by Dissident » Mon Dec 11, 2006 1:55 pm
by Punk Rooster » Mon Dec 11, 2006 2:05 pm
Dissident wrote:Lets say you're on a game show and there's three doors to choose a prize from.
One door has a donkey
Another door also has a donkey
The third of the doors has a car.
You choose one of the doors. Your percentage chance of getting the correct door and therefore the car, is 33.3%
Before opening your door, one of the doors you didn't choose is opened, revealing a donkey.
Question is, if you have the ability to now change your chosen door to the other one that is left, do you increase your chances of getting the car?
Yes. Despite only having two doors left, the odds of having the right door are not 50/50. When choosing the first door, your odds were 1 in 3 ... and despite showing another wrong door, your odds don't change. Therefore, there is a 66.6% chance that you will not get the car by keeping the same door.
Sorry if this doesn't make sense, I'm not sure how to explain it.
To cut a long story short, there is 2 in 3 chance of you getting the car if you change the door after a wrong door being revealed, yet a 1 in 3 chance if you don't change. At the start, it is more likely you have not won the car, and after opening a wrong door, it is still more likely you don't have the car.
Ralph Wiggum wrote:That's where I saw the leprechaun. He told me to burn things
by Dissident » Mon Dec 11, 2006 2:09 pm
Punk Rooster wrote:Dissident wrote:Lets say you're on a game show and there's three doors to choose a prize from.
One door has a donkey
Another door also has a donkey
The third of the doors has a car.
You choose one of the doors. Your percentage chance of getting the correct door and therefore the car, is 33.3%
Before opening your door, one of the doors you didn't choose is opened, revealing a donkey.
Question is, if you have the ability to now change your chosen door to the other one that is left, do you increase your chances of getting the car?
Yes. Despite only having two doors left, the odds of having the right door are not 50/50. When choosing the first door, your odds were 1 in 3 ... and despite showing another wrong door, your odds don't change. Therefore, there is a 66.6% chance that you will not get the car by keeping the same door.
Sorry if this doesn't make sense, I'm not sure how to explain it.
To cut a long story short, there is 2 in 3 chance of you getting the car if you change the door after a wrong door being revealed, yet a 1 in 3 chance if you don't change. At the start, it is more likely you have not won the car, and after opening a wrong door, it is still more likely you don't have the car.
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